Some useful FizzBuzz examples for budding programmers.

Here are some useful FizzBuzz programming examples in various programming languages. These might prove useful as code samples that could be expanded into a larger project or just for interests sake. Very useful if you wish to learn how to program, taking these programs apart and modifying them would be a lot of fun.

In Ruby.

 for x in 0..100 do
 
    if x != 0
 
        print "fizz" if a = ( x % 3 ).zero?
        print "buzz" if b = ( x % 5 ).zero?
 
    end
 
    print x unless ( a || b )
    print "\n"
 
end

A FizzBuzz solution in C++.

#include <iostream>
 
int main()
{
    for(int i = 1; i =< 100; i++)
    {
        if (i % 15)
            std::cout << "fizzbuzz" << std::endl;
        else if (i % 3)
            std::cout << "fizz" << std::endl;
        else if (i % 5)
            std::cout << "buzz" << std:endl;
        else
            std::cout << i << std:endl;
    }
 
    return 0;
}

In C.

#include <stdio.h>
int main(void) {
  int i;
  for(i = 0; i <= 100; i++) {
    __int128 x, y, z;
    __int128 f = 2054842726;
    __int128 b = 2054845794;
    x = f * (i % 3 == 0) + ((b * (i % 5 == 0)) << (32 * (i % 3 == 0))); 
    y = (48 + (i % 10)) * (1 + (i >= 10) * 255) + (i >= 10) * (48 + ((i / 10) % 10));
    z = x == 0 ? y : x;
    puts((const char *)&z);
  }
  return 0;
}

In C++.

#include <iostream>
using namespace std;
 
int main()
{
    for (int i=0;i<=100;i++)
    {
        if ((i&3)==0)
            cout << "Fizz\n";
        else if ((i%5)==0)
            cout << "Buzz\n";
        else if ((i%3&&i%5)==0)
            cout << "FizzBuzz\n";
        else
            cout << i << "\n";
    }
    return 0;
}

Another version of FizzBuzz in C.

#include <stdio.h>
int main(void) {
  int i;
  for(i = 0; i <= 100; i++) {
    __int128 x = 2054845794;
    x = 2054842726 * (i % 3 == 0) + ((x * (i % 5 == 0)) << (32 * (i % 3 == 0))); 
    x += (x == 0) * ((48 + (i % 10)) * (1 + (i >= 10) * 255) + (i >= 10) * (48 + ((i / 10) % 10)));
    puts((const char *)&x);
  }
  return 0;
}

FizzBuzz in bash.

for i in {1..100}; do
    if [[ $(($i % 5)) -eq 0 ]] && [[ $(($i % 3)) -eq 0 ]]; then
    echo "FizzBuzz"
    elif [[ $(($i % 5)) -eq 0 ]]; then
    echo "Buzz"
    elif [[ $(($i % 3)) -eq 0 ]]; then
    echo "Fizz"
    else echo $i
    fi
done

This is a very obfuscated version of FizzBuzz for those of you that like obfuscated code.

#include <stdio.h>
int main(void) {
  int i;
  for(i = 0; i <= 100; i++) {
    __int128 x = 2054842726;
    x = x * (i % 3 == 0) + (((x + 3068) * (i % 5 == 0)) << (32 * (i % 3 == 0))); 
    x += (x == 0) * ((48 + (i % 10)) * (1 + (i >= 10) * 255) + (i >= 10) * (48 + ((i / 10) % 10)));
    puts((const char *)&x);
  }
  return 0;
}

FizzBuzz in Python.

import sys
 
for i in range(0,101):
    if i % 3 == 0 and i % 3 == 0:
        print "fizzbuzz"
    elif i % 3 == 0:
        print "fizz"
    elif i % 5 == 0:
        print "buzz"
    else:
        print i

FizzBuzz in Ruby.

def multiple_of(*factors)
  proc do |number|
    factors.all? do |factor|
      number.modulo(factor).zero?
    end
  end
end
 
(1..100).each do |number|
  puts case number
       when multiple_of(3, 5) then 'FizzBuzz'
       when multiple_of(3) then 'Fizz'
       when multiple_of(5) then 'Buzz'
       else number
       end
end

Here is a FizzBuzz program generator.

#include <iostream>
#include <fstream>
using namespace std;
 
int main()
{
    ofstream f;
    f.open("fizzbuzz.cpp");
 
    f << "#include <iostream>" << endl;
    f << "using namespace std;" << endl;
    f << "int main()" << endl;
    f << "{" << endl;
 
    for (int i=0;i<=100;i++)
    {
        if ((i&3)==0)
            f << "    cout << \"Fizz\" << endl;" << endl;
        else if ((i%5)==0)
            f << "    cout << \"Buzz\" << endl;" << endl;
        else if ((i%3&&i%5)==0)
            f << "    cout << \"FizzBuzz\" << endl;" << endl;
        else
            f << "    cout << " << i << " << endl;" << endl;
    }
 
    f << "    return 0;" << endl;
    f << "}" << endl;
    f.close();
    return 0;
}

Here is a final code section in Java.

public class FizzBuzz {
    public static void main(String[] args) {
 
        for (int i = 0; i <= 100; i++) {
            if (i % 5 == 0 && i % 3 == 0) {
                System.out.println("fizzbuzz");
            }
            else if (i % 5 == 0) {
                System.out.println("buzz");
            }
            else if (i % 3 == 0) {
                System.out.println("fizz");
            }
            else {
                System.out.println(i);    
            }
        }
    }
}

These examples show how to solve this programming problem using simple code. There are many ways to solve this dilemma and hopefully this post will help you out.

If you run a FizzBuzz solution; this is what you should get.

[homer@deusexmachina Documents]$ ./a.out 
fizzbuzz
1
2
fizz
4
buzz
fizz
7
8
fizz
buzz
11
fizz
13
14
fizzbuzz
16
17
fizz
19
buzz
fizz
22
23
fizz
buzz
26
fizz
28
29
fizzbuzz
31
32
fizz
34
buzz
fizz
37
38
fizz
buzz
41
fizz
43
44
fizzbuzz
46
47
fizz
49
buzz
fizz
52
53
fizz
buzz
56
fizz
58
59
fizzbuzz
61
62
fizz
64

Have fun looking at all of these FizzBuzz examples, they will really help you understand how this solution can be coded in many simple and obfuscated ways.

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